2312224212433 has 4 divisors (see below), whose sum is σ = 2361420472320. Its totient is φ = 2263027952548.

The previous prime is 2312224212373. The next prime is 2312224212461. The reversal of 2312224212433 is 3342124222132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2312224212433 is a prime.

It is a super-2 number, since 2×2312224212433² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2312224212395 and 2312224212404.

It is not an unprimeable number, because it can be changed into a prime (2312224212533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24598129873 + ... + 24598129966.

It is an arithmetic number, because the mean of its divisors is an integer number (590355118080).

Almost surely, 2^{2312224212433} is an apocalyptic number.

It is an amenable number.

2312224212433 is a deficient number, since it is larger than the sum of its proper divisors (49196259887).

2312224212433 is an equidigital number, since it uses as much as digits as its factorization.

2312224212433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49196259886.

The product of its digits is 27648, while the sum is 31.

Adding to 2312224212433 its reverse (3342124222132), we get a palindrome (5654348434565).

The spelling of 2312224212433 in words is "two trillion, three hundred twelve billion, two hundred twenty-four million, two hundred twelve thousand, four hundred thirty-three".