Base | Representation |
---|---|
bin | 110100100100110101111011… |
… | …111101110111111010110011 |
3 | 1010022201101122120212222100002 |
4 | 310210311323331313322303 |
5 | 220301434004414212042 |
6 | 2135441411511420215 |
7 | 66463555521421655 |
oct | 6444657375677263 |
9 | 1108641576788302 |
10 | 231230234132147 |
11 | 6774a21200a468 |
12 | 21b25b7568466b |
13 | 9c03bc0a25c43 |
14 | 4115862a8c6d5 |
15 | 1baec67eca132 |
hex | d24d7bf77eb3 |
231230234132147 has 2 divisors, whose sum is σ = 231230234132148. Its totient is φ = 231230234132146.
The previous prime is 231230234132123. The next prime is 231230234132251. The reversal of 231230234132147 is 741231432032132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 231230234132147 - 224 = 231230217354931 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 231230234132147.
It is not a weakly prime, because it can be changed into another prime (231230234132747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115615117066073 + 115615117066074.
It is an arithmetic number, because the mean of its divisors is an integer number (115615117066074).
Almost surely, 2231230234132147 is an apocalyptic number.
231230234132147 is a deficient number, since it is larger than the sum of its proper divisors (1).
231230234132147 is an equidigital number, since it uses as much as digits as its factorization.
231230234132147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 38.
Adding to 231230234132147 its reverse (741231432032132), we get a palindrome (972461666164279).
The spelling of 231230234132147 in words is "two hundred thirty-one trillion, two hundred thirty billion, two hundred thirty-four million, one hundred thirty-two thousand, one hundred forty-seven".
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