Base | Representation |
---|---|
bin | 10101100010010011… |
… | …000011110101101111 |
3 | 2012200112212220202120 |
4 | 111202103003311233 |
5 | 334324221000421 |
6 | 14342323324023 |
7 | 1446014520642 |
oct | 254223036557 |
9 | 65615786676 |
10 | 23124000111 |
11 | 98969935a3 |
12 | 4594220613 |
13 | 2246986a04 |
14 | 1195169a59 |
15 | 9051558c6 |
hex | 5624c3d6f |
23124000111 has 16 divisors (see below), whose sum is σ = 30929996640. Its totient is φ = 15367080960.
The previous prime is 23124000101. The next prime is 23124000121. The reversal of 23124000111 is 11100042132.
It is an interprime number because it is at equal distance from previous prime (23124000101) and next prime (23124000121).
It is not a de Polignac number, because 23124000111 - 215 = 23123967343 is a prime.
It is a super-2 number, since 2×231240001112 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23124000101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1241991 + ... + 1260471.
It is an arithmetic number, because the mean of its divisors is an integer number (1933124790).
Almost surely, 223124000111 is an apocalyptic number.
23124000111 is a deficient number, since it is larger than the sum of its proper divisors (7805996529).
23124000111 is a wasteful number, since it uses less digits than its factorization.
23124000111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19786.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 23124000111 its reverse (11100042132), we get a palindrome (34224042243).
The spelling of 23124000111 in words is "twenty-three billion, one hundred twenty-four million, one hundred eleven", and thus it is an aban number.
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