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231241119937 is a prime number
BaseRepresentation
bin1101011101011100001…
…0110111100011000001
3211002212120222000100121
43113113002313203001
512242040211314222
6254121455420241
722464241042222
oct3272702674301
9732776860317
10231241119937
118a083646a93
1238996224681
1318a62874c69
14b2992c1249
15603600c5c7
hex35d70b78c1

231241119937 has 2 divisors, whose sum is σ = 231241119938. Its totient is φ = 231241119936.

The previous prime is 231241119929. The next prime is 231241119943. The reversal of 231241119937 is 739911142132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 221510481201 + 9730638736 = 470649^2 + 98644^2 .

It is a cyclic number.

It is not a de Polignac number, because 231241119937 - 23 = 231241119929 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 231241119893 and 231241119902.

It is not a weakly prime, because it can be changed into another prime (231241119917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115620559968 + 115620559969.

It is an arithmetic number, because the mean of its divisors is an integer number (115620559969).

Almost surely, 2231241119937 is an apocalyptic number.

It is an amenable number.

231241119937 is a deficient number, since it is larger than the sum of its proper divisors (1).

231241119937 is an equidigital number, since it uses as much as digits as its factorization.

231241119937 is an evil number, because the sum of its binary digits is even.

The product of its digits is 81648, while the sum is 43.

The spelling of 231241119937 in words is "two hundred thirty-one billion, two hundred forty-one million, one hundred nineteen thousand, nine hundred thirty-seven".