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2312612454083 is a prime number
BaseRepresentation
bin100001101001110010011…
…100011001111011000011
322012002020221022221010012
4201221302130121323003
5300342212242012313
64530222142455135
7326036456343521
oct41516234317303
98162227287105
102312612454083
11811856493558
123142492944ab
1313a103393c59
147dd06ab9311
1540252a89da8
hex21a72719ec3

2312612454083 has 2 divisors, whose sum is σ = 2312612454084. Its totient is φ = 2312612454082.

The previous prime is 2312612454029. The next prime is 2312612454109. The reversal of 2312612454083 is 3804542162132.

2312612454083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2312612454083 - 228 = 2312344018627 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2312612454083.

It is not a weakly prime, because it can be changed into another prime (2312612454283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156306227041 + 1156306227042.

It is an arithmetic number, because the mean of its divisors is an integer number (1156306227042).

Almost surely, 22312612454083 is an apocalyptic number.

2312612454083 is a deficient number, since it is larger than the sum of its proper divisors (1).

2312612454083 is an equidigital number, since it uses as much as digits as its factorization.

2312612454083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 276480, while the sum is 41.

The spelling of 2312612454083 in words is "two trillion, three hundred twelve billion, six hundred twelve million, four hundred fifty-four thousand, eighty-three".