Base | Representation |
---|---|
bin | 1010100001001010111110… |
… | …11100100110001111001011 |
3 | 10000220012120111002021001201 |
4 | 11100211133130212033023 |
5 | 11012430220024034011 |
6 | 121105435253325031 |
7 | 4605041652644026 |
oct | 520453734461713 |
9 | 100805514067051 |
10 | 23130000221131 |
11 | 7408418143aa1 |
12 | 27168ba336777 |
13 | cba1c3a64cbb |
14 | 59d6d867a1bd |
15 | 2a19e7483cc1 |
hex | 15095f7263cb |
23130000221131 has 2 divisors, whose sum is σ = 23130000221132. Its totient is φ = 23130000221130.
The previous prime is 23130000221123. The next prime is 23130000221147. The reversal of 23130000221131 is 13112200003132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23130000221131 - 23 = 23130000221123 is a prime.
It is a super-2 number, since 2×231300002211312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23130000221099 and 23130000221108.
It is not a weakly prime, because it can be changed into another prime (23130003221131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11565000110565 + 11565000110566.
It is an arithmetic number, because the mean of its divisors is an integer number (11565000110566).
Almost surely, 223130000221131 is an apocalyptic number.
23130000221131 is a deficient number, since it is larger than the sum of its proper divisors (1).
23130000221131 is an equidigital number, since it uses as much as digits as its factorization.
23130000221131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 23130000221131 its reverse (13112200003132), we get a palindrome (36242200224263).
The spelling of 23130000221131 in words is "twenty-three trillion, one hundred thirty billion, two hundred twenty-one thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •