Base | Representation |
---|---|
bin | 110100100101110111000010… |
… | …001001101011110001111011 |
3 | 1010022222002001211101100102000 |
4 | 310211313002021223301323 |
5 | 220304110132031010021 |
6 | 2135533451402312043 |
7 | 66501611605061355 |
oct | 6445670211536173 |
9 | 1108862054340360 |
10 | 231300131110011 |
11 | 67776920036477 |
12 | 21b37621ab8623 |
13 | 9c0a67ca0c342 |
14 | 4118db3b280d5 |
15 | 1bb19a953ab26 |
hex | d25dc226bc7b |
231300131110011 has 8 divisors (see below), whose sum is σ = 342666860903760. Its totient is φ = 154200087406656.
The previous prime is 231300131109881. The next prime is 231300131110033. The reversal of 231300131110011 is 110011131003132.
231300131110011 is a `hidden beast` number, since 2 + 31 + 300 + 1 + 311 + 10 + 0 + 11 = 666.
It is not a de Polignac number, because 231300131110011 - 245 = 196115759021179 is a prime.
It is not an unprimeable number, because it can be changed into a prime (231300131111011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4283335761270 + ... + 4283335761323.
It is an arithmetic number, because the mean of its divisors is an integer number (42833357612970).
Almost surely, 2231300131110011 is an apocalyptic number.
231300131110011 is a deficient number, since it is larger than the sum of its proper divisors (111366729793749).
231300131110011 is an equidigital number, since it uses as much as digits as its factorization.
231300131110011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8566671522602 (or 8566671522596 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 231300131110011 its reverse (110011131003132), we get a palindrome (341311262113143).
The spelling of 231300131110011 in words is "two hundred thirty-one trillion, three hundred billion, one hundred thirty-one million, one hundred ten thousand, eleven".
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