Base | Representation |
---|---|
bin | 1000100111011101… |
… | …1001110000100001 |
3 | 12222012022200021101 |
4 | 2021313121300201 |
5 | 14214112031032 |
6 | 1021303354401 |
7 | 111214123054 |
oct | 21167316041 |
9 | 5865280241 |
10 | 2313002017 |
11 | a876a1717 |
12 | 546752a01 |
13 | 2ab278261 |
14 | 17d294a9b |
15 | d80ddde7 |
hex | 89dd9c21 |
2313002017 has 2 divisors, whose sum is σ = 2313002018. Its totient is φ = 2313002016.
The previous prime is 2313002011. The next prime is 2313002057. The reversal of 2313002017 is 7102003132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1925542161 + 387459856 = 43881^2 + 19684^2 .
It is a cyclic number.
It is not a de Polignac number, because 2313002017 - 219 = 2312477729 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2313001985 and 2313002003.
It is not a weakly prime, because it can be changed into another prime (2313002011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156501008 + 1156501009.
It is an arithmetic number, because the mean of its divisors is an integer number (1156501009).
Almost surely, 22313002017 is an apocalyptic number.
It is an amenable number.
2313002017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2313002017 is an equidigital number, since it uses as much as digits as its factorization.
2313002017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 19.
The square root of 2313002017 is about 48093.6795951401. The cubic root of 2313002017 is about 1322.4888033329.
Adding to 2313002017 its reverse (7102003132), we get a palindrome (9415005149).
The spelling of 2313002017 in words is "two billion, three hundred thirteen million, two thousand, seventeen".
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