Base | Representation |
---|---|
bin | 100001101010001011011… |
… | …001111010011001001011 |
3 | 22012010100010100000010021 |
4 | 201222023121322121023 |
5 | 300344041443343201 |
6 | 4530331502401311 |
7 | 326053033031602 |
oct | 41521331723113 |
9 | 8163303300107 |
10 | 2313031231051 |
11 | 811a50913922 |
12 | 314345590237 |
13 | 13a16c07b088 |
14 | 7dd4656aa39 |
15 | 4027970bea1 |
hex | 21a8b67a64b |
2313031231051 has 2 divisors, whose sum is σ = 2313031231052. Its totient is φ = 2313031231050.
The previous prime is 2313031230997. The next prime is 2313031231061. The reversal of 2313031231051 is 1501321303132.
2313031231051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2313031231051 is a prime.
It is a super-3 number, since 3×23130312310513 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (2313031231061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156515615525 + 1156515615526.
It is an arithmetic number, because the mean of its divisors is an integer number (1156515615526).
Almost surely, 22313031231051 is an apocalyptic number.
2313031231051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2313031231051 is an equidigital number, since it uses as much as digits as its factorization.
2313031231051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 2313031231051 its reverse (1501321303132), we get a palindrome (3814352534183).
The spelling of 2313031231051 in words is "two trillion, three hundred thirteen billion, thirty-one million, two hundred thirty-one thousand, fifty-one".
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