Base | Representation |
---|---|
bin | 1010100001001101010001… |
… | …10000100110011001101011 |
3 | 10000220022202012111201212101 |
4 | 11100212220300212121223 |
5 | 11012440224412421301 |
6 | 121110201312154231 |
7 | 4605114306416341 |
oct | 520465060463153 |
9 | 100808665451771 |
10 | 23131230201451 |
11 | 7408999467459 |
12 | 2716ba2238977 |
13 | cba35b8254c8 |
14 | 59d7b3b71991 |
15 | 2a1a6a442701 |
hex | 1509a8c2666b |
23131230201451 has 8 divisors (see below), whose sum is σ = 23784249026384. Its totient is φ = 22479677189280.
The previous prime is 23131230201437. The next prime is 23131230201523. The reversal of 23131230201451 is 15410203213132.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23131230201451 - 217 = 23131230070379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23131230201851) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 366421185 + ... + 366484306.
It is an arithmetic number, because the mean of its divisors is an integer number (2973031128298).
Almost surely, 223131230201451 is an apocalyptic number.
23131230201451 is a deficient number, since it is larger than the sum of its proper divisors (653018824933).
23131230201451 is an equidigital number, since it uses as much as digits as its factorization.
23131230201451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 732906381.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 23131230201451 its reverse (15410203213132), we get a palindrome (38541433414583).
The spelling of 23131230201451 in words is "twenty-three trillion, one hundred thirty-one billion, two hundred thirty million, two hundred one thousand, four hundred fifty-one".
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