Base | Representation |
---|---|
bin | 1101011101101101010… |
… | …1110111101100101001 |
3 | 211010001121121120112121 |
4 | 3113123111313230221 |
5 | 12242212140211103 |
6 | 254132552511241 |
7 | 22466104562614 |
oct | 3273325675451 |
9 | 733047546477 |
10 | 231313210153 |
11 | 8a110305483 |
12 | 389b63ab521 |
13 | 18a74795cac |
14 | b2a4ac917b |
15 | 603c4ec6bd |
hex | 35db577b29 |
231313210153 has 2 divisors, whose sum is σ = 231313210154. Its totient is φ = 231313210152.
The previous prime is 231313210129. The next prime is 231313210159. The reversal of 231313210153 is 351012313132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 196930037824 + 34383172329 = 443768^2 + 185427^2 .
It is a cyclic number.
It is not a de Polignac number, because 231313210153 - 233 = 222723275561 is a prime.
It is not a weakly prime, because it can be changed into another prime (231313210159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115656605076 + 115656605077.
It is an arithmetic number, because the mean of its divisors is an integer number (115656605077).
Almost surely, 2231313210153 is an apocalyptic number.
It is an amenable number.
231313210153 is a deficient number, since it is larger than the sum of its proper divisors (1).
231313210153 is an equidigital number, since it uses as much as digits as its factorization.
231313210153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 231313210153 its reverse (351012313132), we get a palindrome (582325523285).
The spelling of 231313210153 in words is "two hundred thirty-one billion, three hundred thirteen million, two hundred ten thousand, one hundred fifty-three".
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