Base | Representation |
---|---|
bin | 1101011101101101101… |
… | …0011100111110001011 |
3 | 211010001200212121100100 |
4 | 3113123122130332023 |
5 | 12242212442131103 |
6 | 254133034340443 |
7 | 22466121025035 |
oct | 3273332347613 |
9 | 733050777310 |
10 | 231314411403 |
11 | 8a110a55a49 |
12 | 389b688a723 |
13 | 18a74ac69aa |
14 | b2a4d1cc55 |
15 | 603c6885a3 |
hex | 35db69cf8b |
231314411403 has 24 divisors (see below), whose sum is σ = 337463334000. Its totient is φ = 152668787904.
The previous prime is 231314411399. The next prime is 231314411407. The reversal of 231314411403 is 304114413132.
231314411403 is a `hidden beast` number, since 231 + 3 + 14 + 4 + 11 + 403 = 666.
It is an interprime number because it is at equal distance from previous prime (231314411399) and next prime (231314411407).
It is not a de Polignac number, because 231314411403 - 22 = 231314411399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (231314411407) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1414153 + ... + 1569221.
It is an arithmetic number, because the mean of its divisors is an integer number (14060972250).
Almost surely, 2231314411403 is an apocalyptic number.
231314411403 is a deficient number, since it is larger than the sum of its proper divisors (106148922597).
231314411403 is a wasteful number, since it uses less digits than its factorization.
231314411403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156731 (or 156728 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 231314411403 its reverse (304114413132), we get a palindrome (535428824535).
The spelling of 231314411403 in words is "two hundred thirty-one billion, three hundred fourteen million, four hundred eleven thousand, four hundred three".
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