Base | Representation |
---|---|
bin | 1010100001001111011110… |
… | …10000110001110110000011 |
3 | 10000220102210122020021010111 |
4 | 11100213233100301312003 |
5 | 11013000140214321201 |
6 | 121110514524412151 |
7 | 4605155521406245 |
oct | 520475720616603 |
9 | 100812718207114 |
10 | 23132413042051 |
11 | 7409446113075 |
12 | 27172723a7057 |
13 | cba4b98bc4a1 |
14 | 59d886cb6095 |
15 | 2a1ad91ddb51 |
hex | 1509ef431d83 |
23132413042051 has 4 divisors (see below), whose sum is σ = 23132694749400. Its totient is φ = 23132131334704.
The previous prime is 23132413042021. The next prime is 23132413042069. The reversal of 23132413042051 is 15024031423132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23132413042051 - 27 = 23132413041923 is a prime.
It is a super-3 number, since 3×231324130420513 (a number of 41 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23132413042021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140730466 + ... + 140894743.
It is an arithmetic number, because the mean of its divisors is an integer number (5783173687350).
Almost surely, 223132413042051 is an apocalyptic number.
23132413042051 is a deficient number, since it is larger than the sum of its proper divisors (281707349).
23132413042051 is an equidigital number, since it uses as much as digits as its factorization.
23132413042051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 281707348.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 23132413042051 its reverse (15024031423132), we get a palindrome (38156444465183).
The spelling of 23132413042051 in words is "twenty-three trillion, one hundred thirty-two billion, four hundred thirteen million, forty-two thousand, fifty-one".
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