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231330110113 = 376761409639
BaseRepresentation
bin1101011101110001011…
…0010101101010100001
3211010002210102011221001
43113130112111222201
512242231002010423
6254134355032001
722466401330624
oct3273426255241
9733083364831
10231330110113
118a1198a8693
12389bbb9b601
1318a7813237b
14b2a7047dbb
15603dc39cad
hex35dc595aa1

231330110113 has 4 divisors (see below), whose sum is σ = 231391523520. Its totient is φ = 231268696708.

The previous prime is 231330110047. The next prime is 231330110159. The reversal of 231330110113 is 311011033132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-231330110113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (231330110413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30701053 + ... + 30708586.

It is an arithmetic number, because the mean of its divisors is an integer number (57847880880).

Almost surely, 2231330110113 is an apocalyptic number.

It is an amenable number.

231330110113 is a deficient number, since it is larger than the sum of its proper divisors (61413407).

231330110113 is an equidigital number, since it uses as much as digits as its factorization.

231330110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61413406.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 231330110113 its reverse (311011033132), we get a palindrome (542341143245).

The spelling of 231330110113 in words is "two hundred thirty-one billion, three hundred thirty million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 3767 61409639 231330110113