Base | Representation |
---|---|
bin | 1101011101110100000… |
… | …0110000100001000011 |
3 | 211010010120100010202011 |
4 | 3113131000300201003 |
5 | 12242241323331042 |
6 | 254135433233351 |
7 | 22466565003556 |
oct | 3273500604103 |
9 | 733116303664 |
10 | 231341230147 |
11 | 8a1251032a5 |
12 | 38a03862857 |
13 | 18a7a526981 |
14 | b2a870069d |
15 | 603ebd4a17 |
hex | 35dd030843 |
231341230147 has 2 divisors, whose sum is σ = 231341230148. Its totient is φ = 231341230146.
The previous prime is 231341230061. The next prime is 231341230157. The reversal of 231341230147 is 741032143132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 231341230147 - 27 = 231341230019 is a prime.
It is not a weakly prime, because it can be changed into another prime (231341230157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115670615073 + 115670615074.
It is an arithmetic number, because the mean of its divisors is an integer number (115670615074).
Almost surely, 2231341230147 is an apocalyptic number.
231341230147 is a deficient number, since it is larger than the sum of its proper divisors (1).
231341230147 is an equidigital number, since it uses as much as digits as its factorization.
231341230147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 231341230147 its reverse (741032143132), we get a palindrome (972373373279).
The spelling of 231341230147 in words is "two hundred thirty-one billion, three hundred forty-one million, two hundred thirty thousand, one hundred forty-seven".
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