Base | Representation |
---|---|
bin | 110100100110011111111010… |
… | …001010001100111111110001 |
3 | 1010100010021100112220110220221 |
4 | 310212133322022030333301 |
5 | 220310320023213134441 |
6 | 2140005550435133041 |
7 | 66505024330205635 |
oct | 6446377212147761 |
9 | 1110107315813827 |
10 | 231344020443121 |
11 | 677934a2460aa3 |
12 | 21b44030444181 |
13 | 9c118557a6531 |
14 | 411b178a7cdc5 |
15 | 1bb2bc76d78d1 |
hex | d267fa28cff1 |
231344020443121 has 2 divisors, whose sum is σ = 231344020443122. Its totient is φ = 231344020443120.
The previous prime is 231344020443083. The next prime is 231344020443161. The reversal of 231344020443121 is 121344020443132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 191162810954896 + 40181209488225 = 13826164^2 + 6338865^2 .
It is a cyclic number.
It is not a de Polignac number, because 231344020443121 - 223 = 231344012054513 is a prime.
It is not a weakly prime, because it can be changed into another prime (231344020443161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115672010221560 + 115672010221561.
It is an arithmetic number, because the mean of its divisors is an integer number (115672010221561).
Almost surely, 2231344020443121 is an apocalyptic number.
It is an amenable number.
231344020443121 is a deficient number, since it is larger than the sum of its proper divisors (1).
231344020443121 is an equidigital number, since it uses as much as digits as its factorization.
231344020443121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 231344020443121 its reverse (121344020443132), we get a palindrome (352688040886253).
The spelling of 231344020443121 in words is "two hundred thirty-one trillion, three hundred forty-four billion, twenty million, four hundred forty-three thousand, one hundred twenty-one".
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