Base | Representation |
---|---|
bin | 1010100001011111110110… |
… | …00001100011110001100001 |
3 | 10000221021111001000220100102 |
4 | 11100233323001203301201 |
5 | 11013121134240012231 |
6 | 121114530510232145 |
7 | 4605616342110260 |
oct | 520577301436141 |
9 | 100837431026312 |
10 | 23141200313441 |
11 | 7412145318131 |
12 | 2718b051b5655 |
13 | cbb28a279962 |
14 | 5a007bd545d7 |
15 | 2a1e50899acb |
hex | 150bfb063c61 |
23141200313441 has 4 divisors (see below), whose sum is σ = 26447086072512. Its totient is φ = 19835314554372.
The previous prime is 23141200313431. The next prime is 23141200313443. The reversal of 23141200313441 is 14431300214132.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23141200313441 is a prime.
It is not an unprimeable number, because it can be changed into a prime (23141200313443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1652942879525 + ... + 1652942879538.
It is an arithmetic number, because the mean of its divisors is an integer number (6611771518128).
Almost surely, 223141200313441 is an apocalyptic number.
It is an amenable number.
23141200313441 is a deficient number, since it is larger than the sum of its proper divisors (3305885759071).
23141200313441 is an equidigital number, since it uses as much as digits as its factorization.
23141200313441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3305885759070.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 23141200313441 its reverse (14431300214132), we get a palindrome (37572500527573).
The spelling of 23141200313441 in words is "twenty-three trillion, one hundred forty-one billion, two hundred million, three hundred thirteen thousand, four hundred forty-one".
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