Base | Representation |
---|---|
bin | 100001101011010111101… |
… | …001100011100110110001 |
3 | 22012020122021022112122001 |
4 | 201223113221203212301 |
5 | 300404201430303213 |
6 | 4531102435414001 |
7 | 326126524553443 |
oct | 41532751434661 |
9 | 8166567275561 |
10 | 2314310400433 |
11 | 8125479837a9 |
12 | 314641a54301 |
13 | 13a3140a1835 |
14 | 800283c8493 |
15 | 40301b851dd |
hex | 21ad7a639b1 |
2314310400433 has 2 divisors, whose sum is σ = 2314310400434. Its totient is φ = 2314310400432.
The previous prime is 2314310400407. The next prime is 2314310400439. The reversal of 2314310400433 is 3340040134132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1492582654369 + 821727746064 = 1221713^2 + 906492^2 .
It is a cyclic number.
It is not a de Polignac number, because 2314310400433 - 217 = 2314310269361 is a prime.
It is not a weakly prime, because it can be changed into another prime (2314310400439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157155200216 + 1157155200217.
It is an arithmetic number, because the mean of its divisors is an integer number (1157155200217).
Almost surely, 22314310400433 is an apocalyptic number.
It is an amenable number.
2314310400433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2314310400433 is an equidigital number, since it uses as much as digits as its factorization.
2314310400433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 2314310400433 its reverse (3340040134132), we get a palindrome (5654350534565).
The spelling of 2314310400433 in words is "two trillion, three hundred fourteen billion, three hundred ten million, four hundred thousand, four hundred thirty-three".
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