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2314331455153 = 5960376497591
BaseRepresentation
bin100001101011011000111…
…001110111111010110001
322012020200201221020021111
4201223120321313322301
5300404222323031103
64531104510553321
7326130201534454
oct41533071677261
98166621836244
102314331455153
118125588544a3
12314648b08841
1313a318564053
148002b10949b
154030394386d
hex21ad8e77eb1

2314331455153 has 8 divisors (see below), whose sum is σ = 2353947629760. Its totient is φ = 2274728287920.

The previous prime is 2314331455147. The next prime is 2314331455223. The reversal of 2314331455153 is 3515541334132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2314331455153 - 213 = 2314331446961 is a prime.

It is a super-2 number, since 2×23143314551532 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2314331455133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2892613 + ... + 3604978.

It is an arithmetic number, because the mean of its divisors is an integer number (294243453720).

Almost surely, 22314331455153 is an apocalyptic number.

It is an amenable number.

2314331455153 is a deficient number, since it is larger than the sum of its proper divisors (39616174607).

2314331455153 is an equidigital number, since it uses as much as digits as its factorization.

2314331455153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6503687.

The product of its digits is 324000, while the sum is 40.

Adding to 2314331455153 its reverse (3515541334132), we get a palindrome (5829872789285).

The spelling of 2314331455153 in words is "two trillion, three hundred fourteen billion, three hundred thirty-one million, four hundred fifty-five thousand, one hundred fifty-three".

Divisors: 1 59 6037 356183 6497591 383357869 39225956867 2314331455153