Base | Representation |
---|---|
bin | 10101100011011100… |
… | …110101100001100011 |
3 | 2012201220021111021121 |
4 | 111203130311201203 |
5 | 334344143341011 |
6 | 14344254033111 |
7 | 1446341100562 |
oct | 254334654143 |
9 | 65656244247 |
10 | 23143340131 |
11 | 98a68a2a8a |
12 | 459a7a8797 |
13 | 224a998902 |
14 | 1197961bd9 |
15 | 906bc5e71 |
hex | 563735863 |
23143340131 has 2 divisors, whose sum is σ = 23143340132. Its totient is φ = 23143340130.
The previous prime is 23143340111. The next prime is 23143340141. The reversal of 23143340131 is 13104334132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23143340131 - 29 = 23143339619 is a prime.
It is a super-2 number, since 2×231433401312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23143340096 and 23143340105.
It is not a weakly prime, because it can be changed into another prime (23143340111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11571670065 + 11571670066.
It is an arithmetic number, because the mean of its divisors is an integer number (11571670066).
Almost surely, 223143340131 is an apocalyptic number.
23143340131 is a deficient number, since it is larger than the sum of its proper divisors (1).
23143340131 is an equidigital number, since it uses as much as digits as its factorization.
23143340131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 23143340131 its reverse (13104334132), we get a palindrome (36247674263).
The spelling of 23143340131 in words is "twenty-three billion, one hundred forty-three million, three hundred forty thousand, one hundred thirty-one".
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