Base | Representation |
---|---|
bin | 10101100011011111… |
… | …010111001000100001 |
3 | 2012201221112010022021 |
4 | 111203133113020201 |
5 | 334344331031311 |
6 | 14344320141441 |
7 | 1446346525504 |
oct | 254337271041 |
9 | 65657463267 |
10 | 23144002081 |
11 | 98a7205352 |
12 | 459aa67881 |
13 | 224ab6acb5 |
14 | 1197a9513b |
15 | 906ca7171 |
hex | 5637d7221 |
23144002081 has 2 divisors, whose sum is σ = 23144002082. Its totient is φ = 23144002080.
The previous prime is 23144002069. The next prime is 23144002129. The reversal of 23144002081 is 18020044132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16785534481 + 6358467600 = 129559^2 + 79740^2 .
It is a cyclic number.
It is not a de Polignac number, because 23144002081 - 27 = 23144001953 is a prime.
It is a super-2 number, since 2×231440020812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (23144002051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11572001040 + 11572001041.
It is an arithmetic number, because the mean of its divisors is an integer number (11572001041).
Almost surely, 223144002081 is an apocalyptic number.
It is an amenable number.
23144002081 is a deficient number, since it is larger than the sum of its proper divisors (1).
23144002081 is an equidigital number, since it uses as much as digits as its factorization.
23144002081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
The spelling of 23144002081 in words is "twenty-three billion, one hundred forty-four million, two thousand, eighty-one".
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