Base | Representation |
---|---|
bin | 10101100011011111… |
… | …010111011101101001 |
3 | 2012201221112012011100 |
4 | 111203133113131221 |
5 | 334344331102213 |
6 | 14344320152013 |
7 | 1446346532445 |
oct | 254337273551 |
9 | 65657465140 |
10 | 23144003433 |
11 | 98a7206371 |
12 | 459aa68609 |
13 | 224ab6b7b5 |
14 | 1197a95825 |
15 | 906ca7773 |
hex | 5637d7769 |
23144003433 has 6 divisors (see below), whose sum is σ = 33430227194. Its totient is φ = 15429335616.
The previous prime is 23144003431. The next prime is 23144003453. The reversal of 23144003433 is 33430044132.
23144003433 is a `hidden beast` number, since 2 + 314 + 4 + 0 + 0 + 343 + 3 = 666.
It can be written as a sum of positive squares in only one way, i.e., 22712901264 + 431102169 = 150708^2 + 20763^2 .
It is not a de Polignac number, because 23144003433 - 21 = 23144003431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23144003397 and 23144003406.
It is not an unprimeable number, because it can be changed into a prime (23144003431) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1285777960 + ... + 1285777977.
Almost surely, 223144003433 is an apocalyptic number.
It is an amenable number.
23144003433 is a deficient number, since it is larger than the sum of its proper divisors (10286223761).
23144003433 is a wasteful number, since it uses less digits than its factorization.
23144003433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2571555943 (or 2571555940 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 27.
Adding to 23144003433 its reverse (33430044132), we get a palindrome (56574047565).
The spelling of 23144003433 in words is "twenty-three billion, one hundred forty-four million, three thousand, four hundred thirty-three".
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