23144012111323 has 4 divisors (see below), whose sum is σ = 23144590621480. Its totient is φ = 23143433601168.

The previous prime is 23144012111287. The next prime is 23144012111351. The reversal of 23144012111323 is 32311121044132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23144012111323 - 2¹³ = 23144012103131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23144012111291 and 23144012111300.

It is not an unprimeable number, because it can be changed into a prime (23144012111923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289195065 + ... + 289275082.

It is an arithmetic number, because the mean of its divisors is an integer number (5786147655370).

Almost surely, 2^{23144012111323} is an apocalyptic number.

23144012111323 is a deficient number, since it is larger than the sum of its proper divisors (578510157).

23144012111323 is an equidigital number, since it uses as much as digits as its factorization.

23144012111323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 578510156.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 23144012111323 its reverse (32311121044132), we get a palindrome (55455133155455).

The spelling of 23144012111323 in words is "twenty-three trillion, one hundred forty-four billion, twelve million, one hundred eleven thousand, three hundred twenty-three".