Base | Representation |
---|---|
bin | 100001101011100011101… |
… | …100010001101101001001 |
3 | 22012021011100111020000001 |
4 | 201223203230101231021 |
5 | 300410110141041022 |
6 | 4531134454043001 |
7 | 326134530064462 |
oct | 41534354215511 |
9 | 8167140436001 |
10 | 2314512440137 |
11 | 812640a2a167 |
12 | 314699649461 |
13 | 13a346bc1361 |
14 | 8004717bd69 |
15 | 40314793b27 |
hex | 21ae3b11b49 |
2314512440137 has 2 divisors, whose sum is σ = 2314512440138. Its totient is φ = 2314512440136.
The previous prime is 2314512440029. The next prime is 2314512440167. The reversal of 2314512440137 is 7310442154132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1634961166336 + 679551273801 = 1278656^2 + 824349^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2314512440137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2314512440096 and 2314512440105.
It is not a weakly prime, because it can be changed into another prime (2314512440167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157256220068 + 1157256220069.
It is an arithmetic number, because the mean of its divisors is an integer number (1157256220069).
Almost surely, 22314512440137 is an apocalyptic number.
It is an amenable number.
2314512440137 is a deficient number, since it is larger than the sum of its proper divisors (1).
2314512440137 is an equidigital number, since it uses as much as digits as its factorization.
2314512440137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 37.
Adding to 2314512440137 its reverse (7310442154132), we get a palindrome (9624954594269).
The spelling of 2314512440137 in words is "two trillion, three hundred fourteen billion, five hundred twelve million, four hundred forty thousand, one hundred thirty-seven".
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