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23145133411 is a prime number
BaseRepresentation
bin10101100011100011…
…101011010101100011
32012202000122121012101
4111203203223111203
5334400123232121
614344400311231
71446362250031
oct254343532543
965660577171
1023145133411
1198a7908334
12459b312517
13224b175c1a
141197cab551
15906e2c491
hex5638eb563

23145133411 has 2 divisors, whose sum is σ = 23145133412. Its totient is φ = 23145133410.

The previous prime is 23145133393. The next prime is 23145133433. The reversal of 23145133411 is 11433154132.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23145133411 is a prime.

It is a super-2 number, since 2×231451334112 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 23145133411.

It is not a weakly prime, because it can be changed into another prime (23145133211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11572566705 + 11572566706.

It is an arithmetic number, because the mean of its divisors is an integer number (11572566706).

Almost surely, 223145133411 is an apocalyptic number.

23145133411 is a deficient number, since it is larger than the sum of its proper divisors (1).

23145133411 is an equidigital number, since it uses as much as digits as its factorization.

23145133411 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4320, while the sum is 28.

Adding to 23145133411 its reverse (11433154132), we get a palindrome (34578287543).

The spelling of 23145133411 in words is "twenty-three billion, one hundred forty-five million, one hundred thirty-three thousand, four hundred eleven".