Base | Representation |
---|---|
bin | 110100101000000011111010… |
… | …110010111110010110011001 |
3 | 1010100111112112101111002202220 |
4 | 310220003322302332112121 |
5 | 220314044434230012213 |
6 | 2140131150245414253 |
7 | 66515545405432404 |
oct | 6450037262762631 |
9 | 1110445471432686 |
10 | 231451405313433 |
11 | 67824a984124a8 |
12 | 21b609bb40a389 |
13 | 9c1ba0a263b06 |
14 | 4122444802d3b |
15 | 1bb58aee11e23 |
hex | d280facbe599 |
231451405313433 has 16 divisors (see below), whose sum is σ = 327696582018240. Its totient is φ = 144805897012736.
The previous prime is 231451405313417. The next prime is 231451405313567. The reversal of 231451405313433 is 334313504154132.
It is a cyclic number.
It is not a de Polignac number, because 231451405313433 - 24 = 231451405313417 is a prime.
It is not an unprimeable number, because it can be changed into a prime (231451405313033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6539265948 + ... + 6539301341.
It is an arithmetic number, because the mean of its divisors is an integer number (20481036376140).
Almost surely, 2231451405313433 is an apocalyptic number.
It is an amenable number.
231451405313433 is a deficient number, since it is larger than the sum of its proper divisors (96245176704807).
231451405313433 is a wasteful number, since it uses less digits than its factorization.
231451405313433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13078567656.
The product of its (nonzero) digits is 777600, while the sum is 42.
Adding to 231451405313433 its reverse (334313504154132), we get a palindrome (565764909467565).
The spelling of 231451405313433 in words is "two hundred thirty-one trillion, four hundred fifty-one billion, four hundred five million, three hundred thirteen thousand, four hundred thirty-three".
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