Base | Representation |
---|---|
bin | 110100101000110001011110… |
… | …100010110111000111010011 |
3 | 1010100200012210120120222121121 |
4 | 310220301132202313013103 |
5 | 220320400130300420342 |
6 | 2140205440323103111 |
7 | 66522226552644316 |
oct | 6450613642670723 |
9 | 1110605716528547 |
10 | 231500323451347 |
11 | 67843810429555 |
12 | 21b6a391b11a97 |
13 | 9c23504b33852 |
14 | 412496559697d |
15 | 1bb6cc4805067 |
hex | d28c5e8b71d3 |
231500323451347 has 2 divisors, whose sum is σ = 231500323451348. Its totient is φ = 231500323451346.
The previous prime is 231500323451227. The next prime is 231500323451461. The reversal of 231500323451347 is 743154323005132.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-231500323451347 is a prime.
It is a super-2 number, since 2×2315003234513472 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (231500323458347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115750161725673 + 115750161725674.
It is an arithmetic number, because the mean of its divisors is an integer number (115750161725674).
Almost surely, 2231500323451347 is an apocalyptic number.
231500323451347 is a deficient number, since it is larger than the sum of its proper divisors (1).
231500323451347 is an equidigital number, since it uses as much as digits as its factorization.
231500323451347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 907200, while the sum is 43.
Adding to 231500323451347 its reverse (743154323005132), we get a palindrome (974654646456479).
The spelling of 231500323451347 in words is "two hundred thirty-one trillion, five hundred billion, three hundred twenty-three million, four hundred fifty-one thousand, three hundred forty-seven".
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