Base | Representation |
---|---|
bin | 10101100011111110… |
… | …000100011101001001 |
3 | 2012202111200002202221 |
4 | 111203332010131021 |
5 | 334403411131131 |
6 | 14345204454041 |
7 | 1446505123666 |
oct | 254376043511 |
9 | 65674602687 |
10 | 23152052041 |
11 | 9900803408 |
12 | 45a16aa321 |
13 | 224c7290a1 |
14 | 1198b8ca6d |
15 | 907847411 |
hex | 563f84749 |
23152052041 has 2 divisors, whose sum is σ = 23152052042. Its totient is φ = 23152052040.
The previous prime is 23152051991. The next prime is 23152052051. The reversal of 23152052041 is 14025025132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12475996416 + 10676055625 = 111696^2 + 103325^2 .
It is a cyclic number.
It is not a de Polignac number, because 23152052041 - 217 = 23151920969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23152051997 and 23152052015.
It is not a weakly prime, because it can be changed into another prime (23152052051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11576026020 + 11576026021.
It is an arithmetic number, because the mean of its divisors is an integer number (11576026021).
Almost surely, 223152052041 is an apocalyptic number.
It is an amenable number.
23152052041 is a deficient number, since it is larger than the sum of its proper divisors (1).
23152052041 is an equidigital number, since it uses as much as digits as its factorization.
23152052041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 23152052041 its reverse (14025025132), we get a palindrome (37177077173).
The spelling of 23152052041 in words is "twenty-three billion, one hundred fifty-two million, fifty-two thousand, forty-one".
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