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231531421254097 is a prime number
BaseRepresentation
bin110100101001001110011100…
…000111100100000111010001
31010100210012001211121001020211
4310221032130013210013101
5220321402322320112342
62140232022213004121
766524410312625266
oct6451163407440721
91110705054531224
10231531421254097
1167855a19316a88
1221b74410623641
139c2641c78a473
14412627572b26d
151bb79e49cdc17
hexd2939c1e41d1

231531421254097 has 2 divisors, whose sum is σ = 231531421254098. Its totient is φ = 231531421254096.

The previous prime is 231531421254047. The next prime is 231531421254149. The reversal of 231531421254097 is 790452124135132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 218482572696336 + 13048848557761 = 14781156^2 + 3612319^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-231531421254097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 231531421254097.

It is not a weakly prime, because it can be changed into another prime (231531421254017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115765710627048 + 115765710627049.

It is an arithmetic number, because the mean of its divisors is an integer number (115765710627049).

Almost surely, 2231531421254097 is an apocalyptic number.

It is an amenable number.

231531421254097 is a deficient number, since it is larger than the sum of its proper divisors (1).

231531421254097 is an equidigital number, since it uses as much as digits as its factorization.

231531421254097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1814400, while the sum is 49.

The spelling of 231531421254097 in words is "two hundred thirty-one trillion, five hundred thirty-one billion, four hundred twenty-one million, two hundred fifty-four thousand, ninety-seven".