Base | Representation |
---|---|
bin | 110100101001010010001111… |
… | …110110001101001010100011 |
3 | 1010100210120121210221100120011 |
4 | 310221102033312031022203 |
5 | 220321434211122004410 |
6 | 2140233540044225351 |
7 | 66524613534415240 |
oct | 6451221766151243 |
9 | 1110716553840504 |
10 | 231535510344355 |
11 | 67857727520018 |
12 | 21b75171b3b257 |
13 | 9c269219a29b9 |
14 | 41265428325c7 |
15 | 1bb7b839a118a |
hex | d2948fd8d2a3 |
231535510344355 has 16 divisors (see below), whose sum is σ = 317783070797760. Its totient is φ = 158642878787712.
The previous prime is 231535510344331. The next prime is 231535510344361. The reversal of 231535510344355 is 553443015535132.
231535510344355 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 231535510344355 - 25 = 231535510344323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 231535510344299 and 231535510344308.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2590127700 + ... + 2590217089.
It is an arithmetic number, because the mean of its divisors is an integer number (19861441924860).
Almost surely, 2231535510344355 is an apocalyptic number.
231535510344355 is a deficient number, since it is larger than the sum of its proper divisors (86247560453405).
231535510344355 is a wasteful number, since it uses less digits than its factorization.
231535510344355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5180346078.
The product of its (nonzero) digits is 8100000, while the sum is 49.
Adding to 231535510344355 its reverse (553443015535132), we get a palindrome (784978525879487).
The spelling of 231535510344355 in words is "two hundred thirty-one trillion, five hundred thirty-five billion, five hundred ten million, three hundred forty-four thousand, three hundred fifty-five".
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