Base | Representation |
---|---|
bin | 1010100001111000001001… |
… | …11111101100110010110011 |
3 | 10000222112011200000200111212 |
4 | 11100330010333230302303 |
5 | 11013324402120001042 |
6 | 121124530004030335 |
7 | 4606560650630606 |
oct | 520740477546263 |
9 | 100875150020455 |
10 | 23154252500147 |
11 | 74177329a719a |
12 | 271b5483923ab |
13 | cbc58a3c1162 |
14 | 5a09595c633d |
15 | 2a24666a9482 |
hex | 150f04feccb3 |
23154252500147 has 4 divisors (see below), whose sum is σ = 23154373703160. Its totient is φ = 23154131297136.
The previous prime is 23154252500131. The next prime is 23154252500149. The reversal of 23154252500147 is 74100525245132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23154252500147 - 24 = 23154252500131 is a prime.
It is a super-2 number, since 2×231542525001472 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23154252500149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60314498 + ... + 60697175.
It is an arithmetic number, because the mean of its divisors is an integer number (5788593425790).
Almost surely, 223154252500147 is an apocalyptic number.
23154252500147 is a deficient number, since it is larger than the sum of its proper divisors (121203013).
23154252500147 is a wasteful number, since it uses less digits than its factorization.
23154252500147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121203012.
The product of its (nonzero) digits is 336000, while the sum is 41.
Adding to 23154252500147 its reverse (74100525245132), we get a palindrome (97254777745279).
The spelling of 23154252500147 in words is "twenty-three trillion, one hundred fifty-four billion, two hundred fifty-two million, five hundred thousand, one hundred forty-seven".
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