Base | Representation |
---|---|
bin | 100001101100011010100… |
… | …111110010101001110011 |
3 | 22012100112120120212220112 |
4 | 201230122213302221303 |
5 | 300414002101330001 |
6 | 4531410134331535 |
7 | 326166420234644 |
oct | 41543247625163 |
9 | 8170476525815 |
10 | 2315434011251 |
11 | 812a74155189 |
12 | 3148b61b9bab |
13 | 13a462acb2ca |
14 | 800d37116cb |
15 | 4036a631cbb |
hex | 21b1a9f2a73 |
2315434011251 has 4 divisors (see below), whose sum is σ = 2315441294904. Its totient is φ = 2315426727600.
The previous prime is 2315434011239. The next prime is 2315434011269. The reversal of 2315434011251 is 1521104345132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2315434011251 - 218 = 2315433749107 is a prime.
It is a super-2 number, since 2×23154340112512 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2315434013251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3142130 + ... + 3808391.
It is an arithmetic number, because the mean of its divisors is an integer number (578860323726).
Almost surely, 22315434011251 is an apocalyptic number.
2315434011251 is a deficient number, since it is larger than the sum of its proper divisors (7283653).
2315434011251 is an equidigital number, since it uses as much as digits as its factorization.
2315434011251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7283652.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 2315434011251 its reverse (1521104345132), we get a palindrome (3836538356383).
The spelling of 2315434011251 in words is "two trillion, three hundred fifteen billion, four hundred thirty-four million, eleven thousand, two hundred fifty-one".
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