Base | Representation |
---|---|
bin | 10101100100000111… |
… | …001010000001101001 |
3 | 2012202200011010102022 |
4 | 111210013022001221 |
5 | 334410013343103 |
6 | 14345331514225 |
7 | 1446534304634 |
oct | 254407120151 |
9 | 65680133368 |
10 | 23154434153 |
11 | 99020900a4 |
12 | 45a2458975 |
13 | 2250081416 |
14 | 119920cc1b |
15 | 907b68138 |
hex | 5641ca069 |
23154434153 has 2 divisors, whose sum is σ = 23154434154. Its totient is φ = 23154434152.
The previous prime is 23154434119. The next prime is 23154434207. The reversal of 23154434153 is 35143445132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 21009632809 + 2144801344 = 144947^2 + 46312^2 .
It is a cyclic number.
It is not a de Polignac number, because 23154434153 - 210 = 23154433129 is a prime.
It is a super-2 number, since 2×231544341532 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (23154434053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11577217076 + 11577217077.
It is an arithmetic number, because the mean of its divisors is an integer number (11577217077).
Almost surely, 223154434153 is an apocalyptic number.
It is an amenable number.
23154434153 is a deficient number, since it is larger than the sum of its proper divisors (1).
23154434153 is an equidigital number, since it uses as much as digits as its factorization.
23154434153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 86400, while the sum is 35.
Adding to 23154434153 its reverse (35143445132), we get a palindrome (58297879285).
The spelling of 23154434153 in words is "twenty-three billion, one hundred fifty-four million, four hundred thirty-four thousand, one hundred fifty-three".
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