Base | Representation |
---|---|
bin | 110100101001100010000100… |
… | …101101100100011001110011 |
3 | 1010100212012111002101000200100 |
4 | 310221202010231210121303 |
5 | 220322224011332300201 |
6 | 2140245430200323443 |
7 | 66526054615124541 |
oct | 6451420455443163 |
9 | 1110765432330610 |
10 | 231552503400051 |
11 | 678639576762a9 |
12 | 21b78514a73583 |
13 | 9c283cc404342 |
14 | 41272b5624d91 |
15 | 1bb832a755886 |
hex | d29884b64673 |
231552503400051 has 6 divisors (see below), whose sum is σ = 334464727133420. Its totient is φ = 154368335600028.
The previous prime is 231552503400047. The next prime is 231552503400107. The reversal of 231552503400051 is 150004305255132.
231552503400051 is a `hidden beast` number, since 2 + 3 + 1 + 552 + 50 + 3 + 4 + 0 + 0 + 0 + 51 = 666.
It is not a de Polignac number, because 231552503400051 - 22 = 231552503400047 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 231552503399979 and 231552503400015.
It is not an unprimeable number, because it can be changed into a prime (231552503410051) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 12864027966661 + ... + 12864027966678.
Almost surely, 2231552503400051 is an apocalyptic number.
231552503400051 is a deficient number, since it is larger than the sum of its proper divisors (102912223733369).
231552503400051 is a wasteful number, since it uses less digits than its factorization.
231552503400051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25728055933345 (or 25728055933342 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
Adding to 231552503400051 its reverse (150004305255132), we get a palindrome (381556808655183).
The spelling of 231552503400051 in words is "two hundred thirty-one trillion, five hundred fifty-two billion, five hundred three million, four hundred thousand, fifty-one".
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