Base | Representation |
---|---|
bin | 110100110000000110000111… |
… | …000100011110000111011001 |
3 | 1010102110022121211100222202122 |
4 | 310300012013010132013121 |
5 | 220402121144204232441 |
6 | 2141232535422111025 |
7 | 66603462240333104 |
oct | 6460060704360731 |
9 | 1112408554328678 |
10 | 232003514524121 |
11 | 67a181576a217a |
12 | 2202ba0371b475 |
13 | 9c5bab7115962 |
14 | 414105c51d73b |
15 | 1bc4e2567134b |
hex | d3018711e1d9 |
232003514524121 has 2 divisors, whose sum is σ = 232003514524122. Its totient is φ = 232003514524120.
The previous prime is 232003514524043. The next prime is 232003514524189. The reversal of 232003514524121 is 121425415300232.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 174341285114896 + 57662229409225 = 13203836^2 + 7593565^2 .
It is a cyclic number.
It is not a de Polignac number, because 232003514524121 - 234 = 231986334654937 is a prime.
It is not a weakly prime, because it can be changed into another prime (232003514527121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116001757262060 + 116001757262061.
It is an arithmetic number, because the mean of its divisors is an integer number (116001757262061).
Almost surely, 2232003514524121 is an apocalyptic number.
It is an amenable number.
232003514524121 is a deficient number, since it is larger than the sum of its proper divisors (1).
232003514524121 is an equidigital number, since it uses as much as digits as its factorization.
232003514524121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 232003514524121 its reverse (121425415300232), we get a palindrome (353428929824353).
The spelling of 232003514524121 in words is "two hundred thirty-two trillion, three billion, five hundred fourteen million, five hundred twenty-four thousand, one hundred twenty-one".
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