Search a number
-
+
232010011 is a prime number
BaseRepresentation
bin11011101010000…
…11000100011011
3121011120022220101
431311003010123
5433343310021
635004440231
75515024012
oct1565030433
9534508811
10232010011
11109a66612
1265849077
13390b413c
1422b55a79
151557da91
hexdd4311b

232010011 has 2 divisors, whose sum is σ = 232010012. Its totient is φ = 232010010.

The previous prime is 232010003. The next prime is 232010027. The reversal of 232010011 is 110010232.

232010011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 232010011 - 23 = 232010003 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 232010011.

It is not a weakly prime, because it can be changed into another prime (232010041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116005005 + 116005006.

It is an arithmetic number, because the mean of its divisors is an integer number (116005006).

Almost surely, 2232010011 is an apocalyptic number.

232010011 is a deficient number, since it is larger than the sum of its proper divisors (1).

232010011 is an equidigital number, since it uses as much as digits as its factorization.

232010011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 10.

The square root of 232010011 is about 15231.8748353576. The cubic root of 232010011 is about 614.4722032180.

Adding to 232010011 its reverse (110010232), we get a palindrome (342020243).

It can be divided in two parts, 2320 and 10011, that multiplied together give a triangular number (23225520 = T6815).

The spelling of 232010011 in words is "two hundred thirty-two million, ten thousand, eleven".