Base | Representation |
---|---|
bin | 1101100000010100011… |
… | …1001011000100010011 |
3 | 211011212110021102001001 |
4 | 3120011013023010103 |
5 | 12300131041003103 |
6 | 254330305122431 |
7 | 22522344315103 |
oct | 3300507130423 |
9 | 734773242031 |
10 | 232014000403 |
11 | 8a43a944579 |
12 | 38b71029417 |
13 | 18b56a20c93 |
14 | b32dbcb203 |
15 | 607dcc901d |
hex | 36051cb113 |
232014000403 has 2 divisors, whose sum is σ = 232014000404. Its totient is φ = 232014000402.
The previous prime is 232014000377. The next prime is 232014000437. The reversal of 232014000403 is 304000410232.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 232014000403 - 217 = 232013869331 is a prime.
It is not a weakly prime, because it can be changed into another prime (232014000473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116007000201 + 116007000202.
It is an arithmetic number, because the mean of its divisors is an integer number (116007000202).
Almost surely, 2232014000403 is an apocalyptic number.
232014000403 is a deficient number, since it is larger than the sum of its proper divisors (1).
232014000403 is an equidigital number, since it uses as much as digits as its factorization.
232014000403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 19.
Adding to 232014000403 its reverse (304000410232), we get a palindrome (536014410635).
The spelling of 232014000403 in words is "two hundred thirty-two billion, fourteen million, four hundred three", and thus it is an aban number.
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