Base | Representation |
---|---|
bin | 10101100111011111… |
… | …011110100100111001 |
3 | 2012220121212011011221 |
4 | 111213133132210321 |
5 | 340014023011213 |
6 | 14355115152041 |
7 | 1451123306164 |
oct | 254737364471 |
9 | 65817764157 |
10 | 23211141433 |
11 | 99310a2117 |
12 | 45b9445621 |
13 | 225ba4771c |
14 | 11a2970adb |
15 | 90cb1a38d |
hex | 5677de939 |
23211141433 has 4 divisors (see below), whose sum is σ = 23211874548. Its totient is φ = 23210408320.
The previous prime is 23211141397. The next prime is 23211141451. The reversal of 23211141433 is 33414111232.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 20137880464 + 3073260969 = 141908^2 + 55437^2 .
It is a cyclic number.
It is not a de Polignac number, because 23211141433 - 225 = 23177587001 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23211141398 and 23211141407.
It is not an unprimeable number, because it can be changed into a prime (23211141463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316816 + ... + 383137.
It is an arithmetic number, because the mean of its divisors is an integer number (5802968637).
Almost surely, 223211141433 is an apocalyptic number.
It is an amenable number.
23211141433 is a deficient number, since it is larger than the sum of its proper divisors (733115).
23211141433 is an equidigital number, since it uses as much as digits as its factorization.
23211141433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 733114.
The product of its digits is 1728, while the sum is 25.
Adding to 23211141433 its reverse (33414111232), we get a palindrome (56625252665).
The spelling of 23211141433 in words is "twenty-three billion, two hundred eleven million, one hundred forty-one thousand, four hundred thirty-three".
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