Base | Representation |
---|---|
bin | 1101100000101100011… |
… | …0001010111111011001 |
3 | 211012010110012022002121 |
4 | 3120023012022333121 |
5 | 12300332241314431 |
6 | 254344253101241 |
7 | 22525003566652 |
oct | 3301306127731 |
9 | 735113168077 |
10 | 232114401241 |
11 | 8a49158a178 |
12 | 38b9a787821 |
13 | 18b71775068 |
14 | b33d284529 |
15 | 6087a0c611 |
hex | 360b18afd9 |
232114401241 has 2 divisors, whose sum is σ = 232114401242. Its totient is φ = 232114401240.
The previous prime is 232114401223. The next prime is 232114401263. The reversal of 232114401241 is 142104411232.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 231934707216 + 179694025 = 481596^2 + 13405^2 .
It is a cyclic number.
It is not a de Polignac number, because 232114401241 - 29 = 232114400729 is a prime.
It is not a weakly prime, because it can be changed into another prime (232114401221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116057200620 + 116057200621.
It is an arithmetic number, because the mean of its divisors is an integer number (116057200621).
Almost surely, 2232114401241 is an apocalyptic number.
It is an amenable number.
232114401241 is a deficient number, since it is larger than the sum of its proper divisors (1).
232114401241 is an equidigital number, since it uses as much as digits as its factorization.
232114401241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 232114401241 its reverse (142104411232), we get a palindrome (374218812473).
Subtracting from 232114401241 its reverse (142104411232), we obtain a palindrome (90009990009).
The spelling of 232114401241 in words is "two hundred thirty-two billion, one hundred fourteen million, four hundred one thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •