Base | Representation |
---|---|
bin | 1010100011100110001110… |
… | …01100111100000101011001 |
3 | 10001012011200221121020110102 |
4 | 11101303013030330011121 |
5 | 11020311412400403101 |
6 | 121212021424225145 |
7 | 4614052223435150 |
oct | 521630714740531 |
9 | 101164627536412 |
10 | 23213345325401 |
11 | 743a7a72a1460 |
12 | 272aa9a46b1b5 |
13 | cc5016c1204a |
14 | 5a37637b2597 |
15 | 2a3c7446486b |
hex | 151cc733c159 |
23213345325401 has 16 divisors (see below), whose sum is σ = 29431844398080. Its totient is φ = 17781739316880.
The previous prime is 23213345325377. The next prime is 23213345325407. The reversal of 23213345325401 is 10452354331232.
It is not a de Polignac number, because 23213345325401 - 214 = 23213345309017 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (23213345325407) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2554843061 + ... + 2554852146.
It is an arithmetic number, because the mean of its divisors is an integer number (1839490274880).
Almost surely, 223213345325401 is an apocalyptic number.
It is an amenable number.
23213345325401 is a deficient number, since it is larger than the sum of its proper divisors (6218499072679).
23213345325401 is a wasteful number, since it uses less digits than its factorization.
23213345325401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5109695284.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 23213345325401 its reverse (10452354331232), we get a palindrome (33665699656633).
The spelling of 23213345325401 in words is "twenty-three trillion, two hundred thirteen billion, three hundred forty-five million, three hundred twenty-five thousand, four hundred one".
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