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23213345325401 = 711595109695207
BaseRepresentation
bin1010100011100110001110…
…01100111100000101011001
310001012011200221121020110102
411101303013030330011121
511020311412400403101
6121212021424225145
74614052223435150
oct521630714740531
9101164627536412
1023213345325401
11743a7a72a1460
12272aa9a46b1b5
13cc5016c1204a
145a37637b2597
152a3c7446486b
hex151cc733c159

23213345325401 has 16 divisors (see below), whose sum is σ = 29431844398080. Its totient is φ = 17781739316880.

The previous prime is 23213345325377. The next prime is 23213345325407. The reversal of 23213345325401 is 10452354331232.

It is not a de Polignac number, because 23213345325401 - 214 = 23213345309017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (23213345325407) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2554843061 + ... + 2554852146.

It is an arithmetic number, because the mean of its divisors is an integer number (1839490274880).

Almost surely, 223213345325401 is an apocalyptic number.

It is an amenable number.

23213345325401 is a deficient number, since it is larger than the sum of its proper divisors (6218499072679).

23213345325401 is a wasteful number, since it uses less digits than its factorization.

23213345325401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5109695284.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 23213345325401 its reverse (10452354331232), we get a palindrome (33665699656633).

The spelling of 23213345325401 in words is "twenty-three trillion, two hundred thirteen billion, three hundred forty-five million, three hundred twenty-five thousand, four hundred one".

Divisors: 1 7 11 59 77 413 649 4543 5109695207 35767866449 56206647277 301472017213 393446530939 2110304120491 3316192189343 23213345325401