Base | Representation |
---|---|
bin | 110100110010001111110000… |
… | …111111111011010111001011 |
3 | 1010102222110010200120220222020 |
4 | 310302033300333323113023 |
5 | 220412031401033344110 |
6 | 2141424502215255523 |
7 | 66620244066316056 |
oct | 6462176077732713 |
9 | 1112873120526866 |
10 | 232151320606155 |
11 | 67a74905345285 |
12 | 2205459367a5a3 |
13 | 9c6ca10cb2bb2 |
14 | 4148280777a9d |
15 | 1bc8bc6835d70 |
hex | d323f0ffb5cb |
232151320606155 has 16 divisors (see below), whose sum is σ = 371442802183200. Its totient is φ = 123813807918848.
The previous prime is 232151320606027. The next prime is 232151320606201. The reversal of 232151320606155 is 551606023151232.
It is a cyclic number.
It is not a de Polignac number, because 232151320606155 - 27 = 232151320606027 is a prime.
It is a super-3 number, since 3×2321513206061553 (a number of 44 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5842152 + ... + 22325621.
It is an arithmetic number, because the mean of its divisors is an integer number (23215175136450).
Almost surely, 2232151320606155 is an apocalyptic number.
232151320606155 is a deficient number, since it is larger than the sum of its proper divisors (139291481577045).
232151320606155 is a wasteful number, since it uses less digits than its factorization.
232151320606155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28717230.
The product of its (nonzero) digits is 324000, while the sum is 42.
Adding to 232151320606155 its reverse (551606023151232), we get a palindrome (783757343757387).
The spelling of 232151320606155 in words is "two hundred thirty-two trillion, one hundred fifty-one billion, three hundred twenty million, six hundred six thousand, one hundred fifty-five".
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