Base | Representation |
---|---|
bin | 1010100011110101010100… |
… | …00000000011100011011011 |
3 | 10001012221121110012210022221 |
4 | 11101322222000003203123 |
5 | 11020430010001442301 |
6 | 121215441255524511 |
7 | 4614460030444135 |
oct | 521725200034333 |
9 | 101187543183287 |
10 | 23221445343451 |
11 | 7443183572953 |
12 | 273057b089737 |
13 | cc5a080a3c34 |
14 | 5a3cd1474055 |
15 | 2a409a619da1 |
hex | 151eaa0038db |
23221445343451 has 4 divisors (see below), whose sum is σ = 23235841777392. Its totient is φ = 23207048909512.
The previous prime is 23221445343427. The next prime is 23221445343469. The reversal of 23221445343451 is 15434354412232.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23221445343451 - 211 = 23221445341403 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23221445343398 and 23221445343407.
It is not an unprimeable number, because it can be changed into a prime (23221445143451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7198214551 + ... + 7198217776.
It is an arithmetic number, because the mean of its divisors is an integer number (5808960444348).
Almost surely, 223221445343451 is an apocalyptic number.
23221445343451 is a deficient number, since it is larger than the sum of its proper divisors (14396433941).
23221445343451 is a wasteful number, since it uses less digits than its factorization.
23221445343451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14396433940.
The product of its digits is 1382400, while the sum is 43.
Adding to 23221445343451 its reverse (15434354412232), we get a palindrome (38655799755683).
The spelling of 23221445343451 in words is "twenty-three trillion, two hundred twenty-one billion, four hundred forty-five million, three hundred forty-three thousand, four hundred fifty-one".
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