Base | Representation |
---|---|
bin | 1010100100000111001001… |
… | …10101110000001101110111 |
3 | 10001020212022220012100120120 |
4 | 11102003210311300031313 |
5 | 11021104113220330033 |
6 | 121224103454103023 |
7 | 4615246251404340 |
oct | 522034465601567 |
9 | 101225286170516 |
10 | 23231022433143 |
11 | 7447248594108 |
12 | 27323b24aaa73 |
13 | cc68a328ab05 |
14 | 5a455d38b0c7 |
15 | 2a445b2db1b3 |
hex | 1520e4d70377 |
23231022433143 has 16 divisors (see below), whose sum is σ = 35446416337920. Its totient is φ = 13257333796896.
The previous prime is 23231022433141. The next prime is 23231022433153. The reversal of 23231022433143 is 34133422013232.
It is not a de Polignac number, because 23231022433143 - 21 = 23231022433141 is a prime.
It is a super-3 number, since 3×232310224331433 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23231022433141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 730657263 + ... + 730689056.
It is an arithmetic number, because the mean of its divisors is an integer number (2215401021120).
Almost surely, 223231022433143 is an apocalyptic number.
23231022433143 is a deficient number, since it is larger than the sum of its proper divisors (12215393904777).
23231022433143 is a wasteful number, since it uses less digits than its factorization.
23231022433143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1461347086.
The product of its (nonzero) digits is 62208, while the sum is 33.
Adding to 23231022433143 its reverse (34133422013232), we get a palindrome (57364444446375).
The spelling of 23231022433143 in words is "twenty-three trillion, two hundred thirty-one billion, twenty-two million, four hundred thirty-three thousand, one hundred forty-three".
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