Base | Representation |
---|---|
bin | 1010100100000111101111… |
… | …10101111001111100110001 |
3 | 10001020220011010002102112010 |
4 | 11102003313311321330301 |
5 | 11021110241324140423 |
6 | 121224155243153133 |
7 | 4615260202253616 |
oct | 522036765717461 |
9 | 101226133072463 |
10 | 23231341240113 |
11 | 74473a1543546 |
12 | 27324812157a9 |
13 | cc6924341ca6 |
14 | 5a458d85850d |
15 | 2a44792b2693 |
hex | 1520f7d79f31 |
23231341240113 has 16 divisors (see below), whose sum is σ = 30997010822400. Its totient is φ = 15476616923664.
The previous prime is 23231341240111. The next prime is 23231341240139. The reversal of 23231341240113 is 31104214313232.
It is not a de Polignac number, because 23231341240113 - 21 = 23231341240111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (23231341240111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 181290538 + ... + 181418636.
It is an arithmetic number, because the mean of its divisors is an integer number (1937313176400).
Almost surely, 223231341240113 is an apocalyptic number.
It is an amenable number.
23231341240113 is a deficient number, since it is larger than the sum of its proper divisors (7765669582287).
23231341240113 is a wasteful number, since it uses less digits than its factorization.
23231341240113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 170348.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 23231341240113 its reverse (31104214313232), we get a palindrome (54335555553345).
The spelling of 23231341240113 in words is "twenty-three trillion, two hundred thirty-one billion, three hundred forty-one million, two hundred forty thousand, one hundred thirteen".
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