2323212400433 has 2 divisors, whose sum is σ = 2323212400434. Its totient is φ = 2323212400432.

The previous prime is 2323212400393. The next prime is 2323212400463. The reversal of 2323212400433 is 3340042123232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2322124917904 + 1087482529 = 1523852^2 + 32977^2 .

It is a cyclic number.

It is not a de Polignac number, because 2323212400433 - 2²⁶ = 2323145291569 is a prime.

It is a super-3 number, since 3×2323212400433³ (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2323212400396 and 2323212400405.

It is not a weakly prime, because it can be changed into another prime (2323212400463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1161606200216 + 1161606200217.

It is an arithmetic number, because the mean of its divisors is an integer number (1161606200217).

Almost surely, 2^{2323212400433} is an apocalyptic number.

It is an amenable number.

2323212400433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2323212400433 is an equidigital number, since it uses as much as digits as its factorization.

2323212400433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 2323212400433 its reverse (3340042123232), we get a palindrome (5663254523665).

The spelling of 2323212400433 in words is "two trillion, three hundred twenty-three billion, two hundred twelve million, four hundred thousand, four hundred thirty-three".