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232323000113 = 571406870403
BaseRepresentation
bin1101100001011110000…
…1111010011100110001
3211012122222201012221202
43120113201322130301
512301244142000423
6254421104100545
722533115626641
oct3302741723461
9735588635852
10232323000113
118a589305636
1239038604755
1318ba5a50249
14b35cc64521
15609aeb4728
hex361787a731

232323000113 has 4 divisors (see below), whose sum is σ = 232729871088. Its totient is φ = 231916129140.

The previous prime is 232323000073. The next prime is 232323000121. The reversal of 232323000113 is 311000323232.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-232323000113 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (232323090113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203434631 + ... + 203435772.

It is an arithmetic number, because the mean of its divisors is an integer number (58182467772).

Almost surely, 2232323000113 is an apocalyptic number.

It is an amenable number.

232323000113 is a deficient number, since it is larger than the sum of its proper divisors (406870975).

232323000113 is an equidigital number, since it uses as much as digits as its factorization.

232323000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 406870974.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 232323000113 its reverse (311000323232), we get a palindrome (543323323345).

The spelling of 232323000113 in words is "two hundred thirty-two billion, three hundred twenty-three million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 571 406870403 232323000113