Base | Representation |
---|---|
bin | 100001110011110101100… |
… | …100111100111001110011 |
3 | 22020010002220121020020022 |
4 | 201303311210330321303 |
5 | 301031312011210103 |
6 | 4535204545434055 |
7 | 326601035632325 |
oct | 41636544747163 |
9 | 8203086536208 |
10 | 2323402444403 |
11 | 816393121a27 |
12 | 31635a93b92b |
13 | 13b13293b201 |
14 | 8064bb1d615 |
15 | 40684e94138 |
hex | 21cf593ce73 |
2323402444403 has 4 divisors (see below), whose sum is σ = 2324723311680. Its totient is φ = 2322081577128.
The previous prime is 2323402444379. The next prime is 2323402444411. The reversal of 2323402444403 is 3044442043232.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2323402444403 - 28 = 2323402444147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2323402444003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 660431000 + ... + 660434517.
It is an arithmetic number, because the mean of its divisors is an integer number (581180827920).
Almost surely, 22323402444403 is an apocalyptic number.
2323402444403 is a deficient number, since it is larger than the sum of its proper divisors (1320867277).
2323402444403 is a wasteful number, since it uses less digits than its factorization.
2323402444403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1320867276.
The product of its (nonzero) digits is 221184, while the sum is 35.
Adding to 2323402444403 its reverse (3044442043232), we get a palindrome (5367844487635).
The spelling of 2323402444403 in words is "two trillion, three hundred twenty-three billion, four hundred two million, four hundred forty-four thousand, four hundred three".
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