Base | Representation |
---|---|
bin | 1010100100001101010010… |
… | …11101001111110010111011 |
3 | 10001021011211210021000212021 |
4 | 11102012221131033302323 |
5 | 11021132342201323233 |
6 | 121225411052255311 |
7 | 4615424064651436 |
oct | 522065135176273 |
9 | 101234753230767 |
10 | 23234321120443 |
11 | 7448690611764 |
12 | 2732b73171537 |
13 | cc6caa8007a4 |
14 | 5a479350481d |
15 | 2a45a0bcee2d |
hex | 1521a974fcbb |
23234321120443 has 2 divisors, whose sum is σ = 23234321120444. Its totient is φ = 23234321120442.
The previous prime is 23234321120411. The next prime is 23234321120489. The reversal of 23234321120443 is 34402112343232.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23234321120443 - 25 = 23234321120411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23234321120399 and 23234321120408.
It is not a weakly prime, because it can be changed into another prime (23234621120443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11617160560221 + 11617160560222.
It is an arithmetic number, because the mean of its divisors is an integer number (11617160560222).
Almost surely, 223234321120443 is an apocalyptic number.
23234321120443 is a deficient number, since it is larger than the sum of its proper divisors (1).
23234321120443 is an equidigital number, since it uses as much as digits as its factorization.
23234321120443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 23234321120443 its reverse (34402112343232), we get a palindrome (57636433463675).
The spelling of 23234321120443 in words is "twenty-three trillion, two hundred thirty-four billion, three hundred twenty-one million, one hundred twenty thousand, four hundred forty-three".
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