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23240411223433 is a prime number
BaseRepresentation
bin1010100100011000101000…
…11101001001010110001001
310001021202120012212022121021
411102030110131021112021
511021232330233122213
6121232255244312441
74616031024661645
oct522142435112611
9101252505768537
1023240411223433
117450226294228
122734192842721
13cc773b456321
145a4bb0289c25
152a480a6b4d8d
hex152314749589

23240411223433 has 2 divisors, whose sum is σ = 23240411223434. Its totient is φ = 23240411223432.

The previous prime is 23240411223391. The next prime is 23240411223457. The reversal of 23240411223433 is 33432211404232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22580477579664 + 659933643769 = 4751892^2 + 812363^2 .

It is a cyclic number.

It is not a de Polignac number, because 23240411223433 - 237 = 23102972269961 is a prime.

It is not a weakly prime, because it can be changed into another prime (23240411223473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11620205611716 + 11620205611717.

It is an arithmetic number, because the mean of its divisors is an integer number (11620205611717).

Almost surely, 223240411223433 is an apocalyptic number.

It is an amenable number.

23240411223433 is a deficient number, since it is larger than the sum of its proper divisors (1).

23240411223433 is an equidigital number, since it uses as much as digits as its factorization.

23240411223433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 82944, while the sum is 34.

Adding to 23240411223433 its reverse (33432211404232), we get a palindrome (56672622627665).

The spelling of 23240411223433 in words is "twenty-three trillion, two hundred forty billion, four hundred eleven million, two hundred twenty-three thousand, four hundred thirty-three".