23240411311209 has 4 divisors (see below), whose sum is σ = 30987215081616. Its totient is φ = 15493607540804.

The previous prime is 23240411311177. The next prime is 23240411311211. The reversal of 23240411311209 is 90211311404232.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23240411311209 - 2⁵ = 23240411311177 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 23240411311209.

It is not an unprimeable number, because it can be changed into a prime (23240411316209) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3873401885199 + ... + 3873401885204.

It is an arithmetic number, because the mean of its divisors is an integer number (7746803770404).

Almost surely, 2^{23240411311209} is an apocalyptic number.

It is an amenable number.

23240411311209 is a deficient number, since it is larger than the sum of its proper divisors (7746803770407).

23240411311209 is an equidigital number, since it uses as much as digits as its factorization.

23240411311209 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7746803770406.

The product of its (nonzero) digits is 10368, while the sum is 33.

The spelling of 23240411311209 in words is "twenty-three trillion, two hundred forty billion, four hundred eleven million, three hundred eleven thousand, two hundred nine".